33042 octal to binary

Here we will show you how to convert the octal number 33042 to a binary number. First note that the octal number system has eight different digits (0 1 2 3 4 5 6 7) and the binary number system has only two different digits (0 and 1).

The four steps used to convert 33042 from octal to binary are explained below.

Step 1)
Multiply the last digit in 33042 by 8⁰, multiply the second to last digit in 33042 by 8¹, multiply the third to last digit in 33042 by 8², multiply the fourth to last digit in 33042 by 8³, and so on, until all the digits are used:

2 × 8⁰ = 2
4 × 8¹ = 32
0 × 8² = 0
3 × 8³ = 1536
3 × 8⁴ = 12288

Step 2)
Next, we add up all the products we got from Step 1, like this:

2 + 32 + 0 + 1536 + 12288 = 13858

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

13858 ÷ 2 = 6929 with 0 remainder
6929 ÷ 2 = 3464 with 1 remainder
3464 ÷ 2 = 1732 with 0 remainder
1732 ÷ 2 = 866 with 0 remainder
866 ÷ 2 = 433 with 0 remainder
433 ÷ 2 = 216 with 1 remainder
216 ÷ 2 = 108 with 0 remainder
108 ÷ 2 = 54 with 0 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 33042 octal to binary:

33042 octal = 11011000100010 binary

Octal to Binary Converter
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33043 octal to binary
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