DB48 hexadecimal to octal

Here we will show you how to convert the hexadecimal number DB48 to an octal number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the octal number system has only eight different digits (0 1 2 3 4 5 6 7).

The four steps used to convert DB48 from hexadecimal to octal are explained below.

Step 1)
Multiply the last digit in DB48 by 16⁰, multiply the second to last digit in DB48 by 16¹, multiply the third to last digit in DB48 by 16², multiply the fourth to last digit in DB48 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
4 × 16¹ = 64
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 64 + 2816 + 53248 = 56136

Step 3)
Now we divide the sum from Step 2 by 8. Put the remainder aside. Then divide the whole part by 8 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56136 ÷ 8 = 7017 with 0 remainder
7017 ÷ 8 = 877 with 1 remainder
877 ÷ 8 = 109 with 5 remainder
109 ÷ 8 = 13 with 5 remainder
13 ÷ 8 = 1 with 5 remainder
1 ÷ 8 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB48 hexadecimal to octal:

DB48 hexadecimal = 155510 octal

Hexadecimal to Octal Converter
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DB49 hexadecimal to octal
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