C2B5 hexadecimal to octal

Here we will show you how to convert the hexadecimal number C2B5 to an octal number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the octal number system has only eight different digits (0 1 2 3 4 5 6 7).

The four steps used to convert C2B5 from hexadecimal to octal are explained below.

Step 1)
Multiply the last digit in C2B5 by 16⁰, multiply the second to last digit in C2B5 by 16¹, multiply the third to last digit in C2B5 by 16², multiply the fourth to last digit in C2B5 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
B × 16¹ = 176
2 × 16² = 512
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 176 + 512 + 49152 = 49845

Step 3)
Now we divide the sum from Step 2 by 8. Put the remainder aside. Then divide the whole part by 8 again, and put the remainder aside again. Keep doing this until the whole part is 0.

49845 ÷ 8 = 6230 with 5 remainder
6230 ÷ 8 = 778 with 6 remainder
778 ÷ 8 = 97 with 2 remainder
97 ÷ 8 = 12 with 1 remainder
12 ÷ 8 = 1 with 4 remainder
1 ÷ 8 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C2B5 hexadecimal to octal:

C2B5 hexadecimal = 141265 octal

Hexadecimal to Octal Converter
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