4DB0 hexadecimal to octal

Here we will show you how to convert the hexadecimal number 4DB0 to an octal number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the octal number system has only eight different digits (0 1 2 3 4 5 6 7).

The four steps used to convert 4DB0 from hexadecimal to octal are explained below.

Step 1)
Multiply the last digit in 4DB0 by 16⁰, multiply the second to last digit in 4DB0 by 16¹, multiply the third to last digit in 4DB0 by 16², multiply the fourth to last digit in 4DB0 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
B × 16¹ = 176
D × 16² = 3328
4 × 16³ = 16384

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 176 + 3328 + 16384 = 19888

Step 3)
Now we divide the sum from Step 2 by 8. Put the remainder aside. Then divide the whole part by 8 again, and put the remainder aside again. Keep doing this until the whole part is 0.

19888 ÷ 8 = 2486 with 0 remainder
2486 ÷ 8 = 310 with 6 remainder
310 ÷ 8 = 38 with 6 remainder
38 ÷ 8 = 4 with 6 remainder
4 ÷ 8 = 0 with 4 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to 4DB0 hexadecimal to octal:

4DB0 hexadecimal = 46660 octal

Hexadecimal to Octal Converter
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