EE55 hexadecimal to binary




Here we will show you how to convert the hexadecimal number EE55 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert EE55 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in EE55 by 16⁰, multiply the second to last digit in EE55 by 16¹, multiply the third to last digit in EE55 by 16², multiply the fourth to last digit in EE55 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
5 × 16¹ = 80
E × 16² = 3584
E × 16³ = 57344

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 80 + 3584 + 57344 = 61013

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

61013 ÷ 2 = 30506 with 1 remainder
30506 ÷ 2 = 15253 with 0 remainder
15253 ÷ 2 = 7626 with 1 remainder
7626 ÷ 2 = 3813 with 0 remainder
3813 ÷ 2 = 1906 with 1 remainder
1906 ÷ 2 = 953 with 0 remainder
953 ÷ 2 = 476 with 1 remainder
476 ÷ 2 = 238 with 0 remainder
238 ÷ 2 = 119 with 0 remainder
119 ÷ 2 = 59 with 1 remainder
59 ÷ 2 = 29 with 1 remainder
29 ÷ 2 = 14 with 1 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to EE55 hexadecimal to binary:

EE55 hexadecimal = 1110111001010101 binary


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EE56 hexadecimal to binary
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