E9B hexadecimal to binary

Here we will show you how to convert the hexadecimal number E9B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert E9B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in E9B by 16⁰, multiply the second to last digit in E9B by 16¹, multiply the third to last digit in E9B by 16², multiply the fourth to last digit in E9B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
9 × 16¹ = 144
E × 16² = 3584

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 144 + 3584 = 3739

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

3739 ÷ 2 = 1869 with 1 remainder
1869 ÷ 2 = 934 with 1 remainder
934 ÷ 2 = 467 with 0 remainder
467 ÷ 2 = 233 with 1 remainder
233 ÷ 2 = 116 with 1 remainder
116 ÷ 2 = 58 with 0 remainder
58 ÷ 2 = 29 with 0 remainder
29 ÷ 2 = 14 with 1 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to E9B hexadecimal to binary:

E9B hexadecimal = 111010011011 binary

Hexadecimal to Binary Converter
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