E4AB hexadecimal to binary

Here we will show you how to convert the hexadecimal number E4AB to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert E4AB from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in E4AB by 16⁰, multiply the second to last digit in E4AB by 16¹, multiply the third to last digit in E4AB by 16², multiply the fourth to last digit in E4AB by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
A × 16¹ = 160
4 × 16² = 1024
E × 16³ = 57344

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 160 + 1024 + 57344 = 58539

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

58539 ÷ 2 = 29269 with 1 remainder
29269 ÷ 2 = 14634 with 1 remainder
14634 ÷ 2 = 7317 with 0 remainder
7317 ÷ 2 = 3658 with 1 remainder
3658 ÷ 2 = 1829 with 0 remainder
1829 ÷ 2 = 914 with 1 remainder
914 ÷ 2 = 457 with 0 remainder
457 ÷ 2 = 228 with 1 remainder
228 ÷ 2 = 114 with 0 remainder
114 ÷ 2 = 57 with 0 remainder
57 ÷ 2 = 28 with 1 remainder
28 ÷ 2 = 14 with 0 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to E4AB hexadecimal to binary:

E4AB hexadecimal = 1110010010101011 binary

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E4AC hexadecimal to binary
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