E45A hexadecimal to binary

Here we will show you how to convert the hexadecimal number E45A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert E45A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in E45A by 16⁰, multiply the second to last digit in E45A by 16¹, multiply the third to last digit in E45A by 16², multiply the fourth to last digit in E45A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
5 × 16¹ = 80
4 × 16² = 1024
E × 16³ = 57344

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 80 + 1024 + 57344 = 58458

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

58458 ÷ 2 = 29229 with 0 remainder
29229 ÷ 2 = 14614 with 1 remainder
14614 ÷ 2 = 7307 with 0 remainder
7307 ÷ 2 = 3653 with 1 remainder
3653 ÷ 2 = 1826 with 1 remainder
1826 ÷ 2 = 913 with 0 remainder
913 ÷ 2 = 456 with 1 remainder
456 ÷ 2 = 228 with 0 remainder
228 ÷ 2 = 114 with 0 remainder
114 ÷ 2 = 57 with 0 remainder
57 ÷ 2 = 28 with 1 remainder
28 ÷ 2 = 14 with 0 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to E45A hexadecimal to binary:

E45A hexadecimal = 1110010001011010 binary

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E45B hexadecimal to binary
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