E428 hexadecimal to binary

Here we will show you how to convert the hexadecimal number E428 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert E428 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in E428 by 16⁰, multiply the second to last digit in E428 by 16¹, multiply the third to last digit in E428 by 16², multiply the fourth to last digit in E428 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
2 × 16¹ = 32
4 × 16² = 1024
E × 16³ = 57344

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 32 + 1024 + 57344 = 58408

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

58408 ÷ 2 = 29204 with 0 remainder
29204 ÷ 2 = 14602 with 0 remainder
14602 ÷ 2 = 7301 with 0 remainder
7301 ÷ 2 = 3650 with 1 remainder
3650 ÷ 2 = 1825 with 0 remainder
1825 ÷ 2 = 912 with 1 remainder
912 ÷ 2 = 456 with 0 remainder
456 ÷ 2 = 228 with 0 remainder
228 ÷ 2 = 114 with 0 remainder
114 ÷ 2 = 57 with 0 remainder
57 ÷ 2 = 28 with 1 remainder
28 ÷ 2 = 14 with 0 remainder
14 ÷ 2 = 7 with 0 remainder
7 ÷ 2 = 3 with 1 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to E428 hexadecimal to binary:

E428 hexadecimal = 1110010000101000 binary

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E429 hexadecimal to binary
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