DDB5 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DDB5 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DDB5 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DDB5 by 16⁰, multiply the second to last digit in DDB5 by 16¹, multiply the third to last digit in DDB5 by 16², multiply the fourth to last digit in DDB5 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
B × 16¹ = 176
D × 16² = 3328
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 176 + 3328 + 53248 = 56757

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56757 ÷ 2 = 28378 with 1 remainder
28378 ÷ 2 = 14189 with 0 remainder
14189 ÷ 2 = 7094 with 1 remainder
7094 ÷ 2 = 3547 with 0 remainder
3547 ÷ 2 = 1773 with 1 remainder
1773 ÷ 2 = 886 with 1 remainder
886 ÷ 2 = 443 with 0 remainder
443 ÷ 2 = 221 with 1 remainder
221 ÷ 2 = 110 with 1 remainder
110 ÷ 2 = 55 with 0 remainder
55 ÷ 2 = 27 with 1 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DDB5 hexadecimal to binary:

DDB5 hexadecimal = 1101110110110101 binary

Hexadecimal to Binary Converter
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