DCC8 hexadecimal to binary




Here we will show you how to convert the hexadecimal number DCC8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert DCC8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DCC8 by 16⁰, multiply the second to last digit in DCC8 by 16¹, multiply the third to last digit in DCC8 by 16², multiply the fourth to last digit in DCC8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
C × 16¹ = 192
C × 16² = 3072
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 192 + 3072 + 53248 = 56520

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56520 ÷ 2 = 28260 with 0 remainder
28260 ÷ 2 = 14130 with 0 remainder
14130 ÷ 2 = 7065 with 0 remainder
7065 ÷ 2 = 3532 with 1 remainder
3532 ÷ 2 = 1766 with 0 remainder
1766 ÷ 2 = 883 with 0 remainder
883 ÷ 2 = 441 with 1 remainder
441 ÷ 2 = 220 with 1 remainder
220 ÷ 2 = 110 with 0 remainder
110 ÷ 2 = 55 with 0 remainder
55 ÷ 2 = 27 with 1 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DCC8 hexadecimal to binary:

DCC8 hexadecimal = 1101110011001000 binary


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