DC58 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DC58 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DC58 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DC58 by 16⁰, multiply the second to last digit in DC58 by 16¹, multiply the third to last digit in DC58 by 16², multiply the fourth to last digit in DC58 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
5 × 16¹ = 80
C × 16² = 3072
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 80 + 3072 + 53248 = 56408

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56408 ÷ 2 = 28204 with 0 remainder
28204 ÷ 2 = 14102 with 0 remainder
14102 ÷ 2 = 7051 with 0 remainder
7051 ÷ 2 = 3525 with 1 remainder
3525 ÷ 2 = 1762 with 1 remainder
1762 ÷ 2 = 881 with 0 remainder
881 ÷ 2 = 440 with 1 remainder
440 ÷ 2 = 220 with 0 remainder
220 ÷ 2 = 110 with 0 remainder
110 ÷ 2 = 55 with 0 remainder
55 ÷ 2 = 27 with 1 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DC58 hexadecimal to binary:

DC58 hexadecimal = 1101110001011000 binary

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DC59 hexadecimal to binary
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