DBC8 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DBC8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DBC8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DBC8 by 16⁰, multiply the second to last digit in DBC8 by 16¹, multiply the third to last digit in DBC8 by 16², multiply the fourth to last digit in DBC8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
C × 16¹ = 192
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 192 + 2816 + 53248 = 56264

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56264 ÷ 2 = 28132 with 0 remainder
28132 ÷ 2 = 14066 with 0 remainder
14066 ÷ 2 = 7033 with 0 remainder
7033 ÷ 2 = 3516 with 1 remainder
3516 ÷ 2 = 1758 with 0 remainder
1758 ÷ 2 = 879 with 0 remainder
879 ÷ 2 = 439 with 1 remainder
439 ÷ 2 = 219 with 1 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DBC8 hexadecimal to binary:

DBC8 hexadecimal = 1101101111001000 binary

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DBC9 hexadecimal to binary
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