DB9B hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB9B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB9B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB9B by 16⁰, multiply the second to last digit in DB9B by 16¹, multiply the third to last digit in DB9B by 16², multiply the fourth to last digit in DB9B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
9 × 16¹ = 144
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 144 + 2816 + 53248 = 56219

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56219 ÷ 2 = 28109 with 1 remainder
28109 ÷ 2 = 14054 with 1 remainder
14054 ÷ 2 = 7027 with 0 remainder
7027 ÷ 2 = 3513 with 1 remainder
3513 ÷ 2 = 1756 with 1 remainder
1756 ÷ 2 = 878 with 0 remainder
878 ÷ 2 = 439 with 0 remainder
439 ÷ 2 = 219 with 1 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB9B hexadecimal to binary:

DB9B hexadecimal = 1101101110011011 binary

Hexadecimal to Binary Converter
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