DB8A hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB8A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB8A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB8A by 16⁰, multiply the second to last digit in DB8A by 16¹, multiply the third to last digit in DB8A by 16², multiply the fourth to last digit in DB8A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
8 × 16¹ = 128
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 128 + 2816 + 53248 = 56202

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56202 ÷ 2 = 28101 with 0 remainder
28101 ÷ 2 = 14050 with 1 remainder
14050 ÷ 2 = 7025 with 0 remainder
7025 ÷ 2 = 3512 with 1 remainder
3512 ÷ 2 = 1756 with 0 remainder
1756 ÷ 2 = 878 with 0 remainder
878 ÷ 2 = 439 with 0 remainder
439 ÷ 2 = 219 with 1 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB8A hexadecimal to binary:

DB8A hexadecimal = 1101101110001010 binary

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DB8B hexadecimal to binary
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