DB85 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB85 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB85 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB85 by 16⁰, multiply the second to last digit in DB85 by 16¹, multiply the third to last digit in DB85 by 16², multiply the fourth to last digit in DB85 by 16³, and so on, until all the digits are used.

5 × 16⁰ = 5
8 × 16¹ = 128
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

5 + 128 + 2816 + 53248 = 56197

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56197 ÷ 2 = 28098 with 1 remainder
28098 ÷ 2 = 14049 with 0 remainder
14049 ÷ 2 = 7024 with 1 remainder
7024 ÷ 2 = 3512 with 0 remainder
3512 ÷ 2 = 1756 with 0 remainder
1756 ÷ 2 = 878 with 0 remainder
878 ÷ 2 = 439 with 0 remainder
439 ÷ 2 = 219 with 1 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB85 hexadecimal to binary:

DB85 hexadecimal = 1101101110000101 binary

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DB86 hexadecimal to binary
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