DB5B hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB5B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB5B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB5B by 16⁰, multiply the second to last digit in DB5B by 16¹, multiply the third to last digit in DB5B by 16², multiply the fourth to last digit in DB5B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
5 × 16¹ = 80
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 80 + 2816 + 53248 = 56155

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56155 ÷ 2 = 28077 with 1 remainder
28077 ÷ 2 = 14038 with 1 remainder
14038 ÷ 2 = 7019 with 0 remainder
7019 ÷ 2 = 3509 with 1 remainder
3509 ÷ 2 = 1754 with 1 remainder
1754 ÷ 2 = 877 with 0 remainder
877 ÷ 2 = 438 with 1 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB5B hexadecimal to binary:

DB5B hexadecimal = 1101101101011011 binary

Hexadecimal to Binary Converter
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