DB57 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB57 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB57 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB57 by 16⁰, multiply the second to last digit in DB57 by 16¹, multiply the third to last digit in DB57 by 16², multiply the fourth to last digit in DB57 by 16³, and so on, until all the digits are used.

7 × 16⁰ = 7
5 × 16¹ = 80
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

7 + 80 + 2816 + 53248 = 56151

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56151 ÷ 2 = 28075 with 1 remainder
28075 ÷ 2 = 14037 with 1 remainder
14037 ÷ 2 = 7018 with 1 remainder
7018 ÷ 2 = 3509 with 0 remainder
3509 ÷ 2 = 1754 with 1 remainder
1754 ÷ 2 = 877 with 0 remainder
877 ÷ 2 = 438 with 1 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB57 hexadecimal to binary:

DB57 hexadecimal = 1101101101010111 binary

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DB58 hexadecimal to binary
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