DB4F hexadecimal to binary




Here we will show you how to convert the hexadecimal number DB4F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert DB4F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB4F by 16⁰, multiply the second to last digit in DB4F by 16¹, multiply the third to last digit in DB4F by 16², multiply the fourth to last digit in DB4F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
4 × 16¹ = 64
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 64 + 2816 + 53248 = 56143

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56143 ÷ 2 = 28071 with 1 remainder
28071 ÷ 2 = 14035 with 1 remainder
14035 ÷ 2 = 7017 with 1 remainder
7017 ÷ 2 = 3508 with 1 remainder
3508 ÷ 2 = 1754 with 0 remainder
1754 ÷ 2 = 877 with 0 remainder
877 ÷ 2 = 438 with 1 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB4F hexadecimal to binary:

DB4F hexadecimal = 1101101101001111 binary


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