DB33 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB33 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB33 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB33 by 16⁰, multiply the second to last digit in DB33 by 16¹, multiply the third to last digit in DB33 by 16², multiply the fourth to last digit in DB33 by 16³, and so on, until all the digits are used.

3 × 16⁰ = 3
3 × 16¹ = 48
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

3 + 48 + 2816 + 53248 = 56115

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56115 ÷ 2 = 28057 with 1 remainder
28057 ÷ 2 = 14028 with 1 remainder
14028 ÷ 2 = 7014 with 0 remainder
7014 ÷ 2 = 3507 with 0 remainder
3507 ÷ 2 = 1753 with 1 remainder
1753 ÷ 2 = 876 with 1 remainder
876 ÷ 2 = 438 with 0 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB33 hexadecimal to binary:

DB33 hexadecimal = 1101101100110011 binary

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DB34 hexadecimal to binary
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