DB2F hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB2F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB2F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB2F by 16⁰, multiply the second to last digit in DB2F by 16¹, multiply the third to last digit in DB2F by 16², multiply the fourth to last digit in DB2F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
2 × 16¹ = 32
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 32 + 2816 + 53248 = 56111

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56111 ÷ 2 = 28055 with 1 remainder
28055 ÷ 2 = 14027 with 1 remainder
14027 ÷ 2 = 7013 with 1 remainder
7013 ÷ 2 = 3506 with 1 remainder
3506 ÷ 2 = 1753 with 0 remainder
1753 ÷ 2 = 876 with 1 remainder
876 ÷ 2 = 438 with 0 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB2F hexadecimal to binary:

DB2F hexadecimal = 1101101100101111 binary

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