DB28 hexadecimal to binary

Here we will show you how to convert the hexadecimal number DB28 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert DB28 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in DB28 by 16⁰, multiply the second to last digit in DB28 by 16¹, multiply the third to last digit in DB28 by 16², multiply the fourth to last digit in DB28 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
2 × 16¹ = 32
B × 16² = 2816
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 32 + 2816 + 53248 = 56104

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

56104 ÷ 2 = 28052 with 0 remainder
28052 ÷ 2 = 14026 with 0 remainder
14026 ÷ 2 = 7013 with 0 remainder
7013 ÷ 2 = 3506 with 1 remainder
3506 ÷ 2 = 1753 with 0 remainder
1753 ÷ 2 = 876 with 1 remainder
876 ÷ 2 = 438 with 0 remainder
438 ÷ 2 = 219 with 0 remainder
219 ÷ 2 = 109 with 1 remainder
109 ÷ 2 = 54 with 1 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to DB28 hexadecimal to binary:

DB28 hexadecimal = 1101101100101000 binary

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DB29 hexadecimal to binary
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