D940 hexadecimal to binary

Here we will show you how to convert the hexadecimal number D940 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D940 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D940 by 16⁰, multiply the second to last digit in D940 by 16¹, multiply the third to last digit in D940 by 16², multiply the fourth to last digit in D940 by 16³, and so on, until all the digits are used.

0 × 16⁰ = 0
4 × 16¹ = 64
9 × 16² = 2304
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

0 + 64 + 2304 + 53248 = 55616

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

55616 ÷ 2 = 27808 with 0 remainder
27808 ÷ 2 = 13904 with 0 remainder
13904 ÷ 2 = 6952 with 0 remainder
6952 ÷ 2 = 3476 with 0 remainder
3476 ÷ 2 = 1738 with 0 remainder
1738 ÷ 2 = 869 with 0 remainder
869 ÷ 2 = 434 with 1 remainder
434 ÷ 2 = 217 with 0 remainder
217 ÷ 2 = 108 with 1 remainder
108 ÷ 2 = 54 with 0 remainder
54 ÷ 2 = 27 with 0 remainder
27 ÷ 2 = 13 with 1 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D940 hexadecimal to binary:

D940 hexadecimal = 1101100101000000 binary

Hexadecimal to Binary Converter
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