D73B hexadecimal to binary

Here we will show you how to convert the hexadecimal number D73B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D73B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D73B by 16⁰, multiply the second to last digit in D73B by 16¹, multiply the third to last digit in D73B by 16², multiply the fourth to last digit in D73B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
3 × 16¹ = 48
7 × 16² = 1792
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 48 + 1792 + 53248 = 55099

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

55099 ÷ 2 = 27549 with 1 remainder
27549 ÷ 2 = 13774 with 1 remainder
13774 ÷ 2 = 6887 with 0 remainder
6887 ÷ 2 = 3443 with 1 remainder
3443 ÷ 2 = 1721 with 1 remainder
1721 ÷ 2 = 860 with 1 remainder
860 ÷ 2 = 430 with 0 remainder
430 ÷ 2 = 215 with 0 remainder
215 ÷ 2 = 107 with 1 remainder
107 ÷ 2 = 53 with 1 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D73B hexadecimal to binary:

D73B hexadecimal = 1101011100111011 binary

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