D5B4 hexadecimal to binary




Here we will show you how to convert the hexadecimal number D5B4 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert D5B4 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D5B4 by 16⁰, multiply the second to last digit in D5B4 by 16¹, multiply the third to last digit in D5B4 by 16², multiply the fourth to last digit in D5B4 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
B × 16¹ = 176
5 × 16² = 1280
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 176 + 1280 + 53248 = 54708

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

54708 ÷ 2 = 27354 with 0 remainder
27354 ÷ 2 = 13677 with 0 remainder
13677 ÷ 2 = 6838 with 1 remainder
6838 ÷ 2 = 3419 with 0 remainder
3419 ÷ 2 = 1709 with 1 remainder
1709 ÷ 2 = 854 with 1 remainder
854 ÷ 2 = 427 with 0 remainder
427 ÷ 2 = 213 with 1 remainder
213 ÷ 2 = 106 with 1 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D5B4 hexadecimal to binary:

D5B4 hexadecimal = 1101010110110100 binary


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D5B5 hexadecimal to binary
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