D558 hexadecimal to binary

Here we will show you how to convert the hexadecimal number D558 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D558 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D558 by 16⁰, multiply the second to last digit in D558 by 16¹, multiply the third to last digit in D558 by 16², multiply the fourth to last digit in D558 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
5 × 16¹ = 80
5 × 16² = 1280
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 80 + 1280 + 53248 = 54616

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

54616 ÷ 2 = 27308 with 0 remainder
27308 ÷ 2 = 13654 with 0 remainder
13654 ÷ 2 = 6827 with 0 remainder
6827 ÷ 2 = 3413 with 1 remainder
3413 ÷ 2 = 1706 with 1 remainder
1706 ÷ 2 = 853 with 0 remainder
853 ÷ 2 = 426 with 1 remainder
426 ÷ 2 = 213 with 0 remainder
213 ÷ 2 = 106 with 1 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D558 hexadecimal to binary:

D558 hexadecimal = 1101010101011000 binary

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D559 hexadecimal to binary
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