D4B8 hexadecimal to binary

Here we will show you how to convert the hexadecimal number D4B8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D4B8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D4B8 by 16⁰, multiply the second to last digit in D4B8 by 16¹, multiply the third to last digit in D4B8 by 16², multiply the fourth to last digit in D4B8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
B × 16¹ = 176
4 × 16² = 1024
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 176 + 1024 + 53248 = 54456

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

54456 ÷ 2 = 27228 with 0 remainder
27228 ÷ 2 = 13614 with 0 remainder
13614 ÷ 2 = 6807 with 0 remainder
6807 ÷ 2 = 3403 with 1 remainder
3403 ÷ 2 = 1701 with 1 remainder
1701 ÷ 2 = 850 with 1 remainder
850 ÷ 2 = 425 with 0 remainder
425 ÷ 2 = 212 with 1 remainder
212 ÷ 2 = 106 with 0 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D4B8 hexadecimal to binary:

D4B8 hexadecimal = 1101010010111000 binary

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D4B9 hexadecimal to binary
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