D41F hexadecimal to binary

Here we will show you how to convert the hexadecimal number D41F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D41F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D41F by 16⁰, multiply the second to last digit in D41F by 16¹, multiply the third to last digit in D41F by 16², multiply the fourth to last digit in D41F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
1 × 16¹ = 16
4 × 16² = 1024
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 16 + 1024 + 53248 = 54303

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

54303 ÷ 2 = 27151 with 1 remainder
27151 ÷ 2 = 13575 with 1 remainder
13575 ÷ 2 = 6787 with 1 remainder
6787 ÷ 2 = 3393 with 1 remainder
3393 ÷ 2 = 1696 with 1 remainder
1696 ÷ 2 = 848 with 0 remainder
848 ÷ 2 = 424 with 0 remainder
424 ÷ 2 = 212 with 0 remainder
212 ÷ 2 = 106 with 0 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D41F hexadecimal to binary:

D41F hexadecimal = 1101010000011111 binary

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D420 hexadecimal to binary
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