D40A hexadecimal to binary

Here we will show you how to convert the hexadecimal number D40A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D40A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D40A by 16⁰, multiply the second to last digit in D40A by 16¹, multiply the third to last digit in D40A by 16², multiply the fourth to last digit in D40A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
0 × 16¹ = 0
4 × 16² = 1024
D × 16³ = 53248

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 0 + 1024 + 53248 = 54282

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

54282 ÷ 2 = 27141 with 0 remainder
27141 ÷ 2 = 13570 with 1 remainder
13570 ÷ 2 = 6785 with 0 remainder
6785 ÷ 2 = 3392 with 1 remainder
3392 ÷ 2 = 1696 with 0 remainder
1696 ÷ 2 = 848 with 0 remainder
848 ÷ 2 = 424 with 0 remainder
424 ÷ 2 = 212 with 0 remainder
212 ÷ 2 = 106 with 0 remainder
106 ÷ 2 = 53 with 0 remainder
53 ÷ 2 = 26 with 1 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D40A hexadecimal to binary:

D40A hexadecimal = 1101010000001010 binary

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D40B hexadecimal to binary
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