D38 hexadecimal to binary

Here we will show you how to convert the hexadecimal number D38 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert D38 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in D38 by 16⁰, multiply the second to last digit in D38 by 16¹, multiply the third to last digit in D38 by 16², multiply the fourth to last digit in D38 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
3 × 16¹ = 48
D × 16² = 3328

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 48 + 3328 = 3384

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

3384 ÷ 2 = 1692 with 0 remainder
1692 ÷ 2 = 846 with 0 remainder
846 ÷ 2 = 423 with 0 remainder
423 ÷ 2 = 211 with 1 remainder
211 ÷ 2 = 105 with 1 remainder
105 ÷ 2 = 52 with 1 remainder
52 ÷ 2 = 26 with 0 remainder
26 ÷ 2 = 13 with 0 remainder
13 ÷ 2 = 6 with 1 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to D38 hexadecimal to binary:

D38 hexadecimal = 110100111000 binary

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D39 hexadecimal to binary
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