C9BA hexadecimal to binary

Here we will show you how to convert the hexadecimal number C9BA to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C9BA from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C9BA by 16⁰, multiply the second to last digit in C9BA by 16¹, multiply the third to last digit in C9BA by 16², multiply the fourth to last digit in C9BA by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
B × 16¹ = 176
9 × 16² = 2304
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 176 + 2304 + 49152 = 51642

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

51642 ÷ 2 = 25821 with 0 remainder
25821 ÷ 2 = 12910 with 1 remainder
12910 ÷ 2 = 6455 with 0 remainder
6455 ÷ 2 = 3227 with 1 remainder
3227 ÷ 2 = 1613 with 1 remainder
1613 ÷ 2 = 806 with 1 remainder
806 ÷ 2 = 403 with 0 remainder
403 ÷ 2 = 201 with 1 remainder
201 ÷ 2 = 100 with 1 remainder
100 ÷ 2 = 50 with 0 remainder
50 ÷ 2 = 25 with 0 remainder
25 ÷ 2 = 12 with 1 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C9BA hexadecimal to binary:

C9BA hexadecimal = 1100100110111010 binary

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C9BB hexadecimal to binary
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