C77B hexadecimal to binary

Here we will show you how to convert the hexadecimal number C77B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C77B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C77B by 16⁰, multiply the second to last digit in C77B by 16¹, multiply the third to last digit in C77B by 16², multiply the fourth to last digit in C77B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
7 × 16¹ = 112
7 × 16² = 1792
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 112 + 1792 + 49152 = 51067

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

51067 ÷ 2 = 25533 with 1 remainder
25533 ÷ 2 = 12766 with 1 remainder
12766 ÷ 2 = 6383 with 0 remainder
6383 ÷ 2 = 3191 with 1 remainder
3191 ÷ 2 = 1595 with 1 remainder
1595 ÷ 2 = 797 with 1 remainder
797 ÷ 2 = 398 with 1 remainder
398 ÷ 2 = 199 with 0 remainder
199 ÷ 2 = 99 with 1 remainder
99 ÷ 2 = 49 with 1 remainder
49 ÷ 2 = 24 with 1 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C77B hexadecimal to binary:

C77B hexadecimal = 1100011101111011 binary

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C77C hexadecimal to binary
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