C58D hexadecimal to binary

Here we will show you how to convert the hexadecimal number C58D to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C58D from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C58D by 16⁰, multiply the second to last digit in C58D by 16¹, multiply the third to last digit in C58D by 16², multiply the fourth to last digit in C58D by 16³, and so on, until all the digits are used.

D × 16⁰ = 13
8 × 16¹ = 128
5 × 16² = 1280
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

13 + 128 + 1280 + 49152 = 50573

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

50573 ÷ 2 = 25286 with 1 remainder
25286 ÷ 2 = 12643 with 0 remainder
12643 ÷ 2 = 6321 with 1 remainder
6321 ÷ 2 = 3160 with 1 remainder
3160 ÷ 2 = 1580 with 0 remainder
1580 ÷ 2 = 790 with 0 remainder
790 ÷ 2 = 395 with 0 remainder
395 ÷ 2 = 197 with 1 remainder
197 ÷ 2 = 98 with 1 remainder
98 ÷ 2 = 49 with 0 remainder
49 ÷ 2 = 24 with 1 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C58D hexadecimal to binary:

C58D hexadecimal = 1100010110001101 binary

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