C57A hexadecimal to binary

Here we will show you how to convert the hexadecimal number C57A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C57A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C57A by 16⁰, multiply the second to last digit in C57A by 16¹, multiply the third to last digit in C57A by 16², multiply the fourth to last digit in C57A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
7 × 16¹ = 112
5 × 16² = 1280
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 112 + 1280 + 49152 = 50554

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

50554 ÷ 2 = 25277 with 0 remainder
25277 ÷ 2 = 12638 with 1 remainder
12638 ÷ 2 = 6319 with 0 remainder
6319 ÷ 2 = 3159 with 1 remainder
3159 ÷ 2 = 1579 with 1 remainder
1579 ÷ 2 = 789 with 1 remainder
789 ÷ 2 = 394 with 1 remainder
394 ÷ 2 = 197 with 0 remainder
197 ÷ 2 = 98 with 1 remainder
98 ÷ 2 = 49 with 0 remainder
49 ÷ 2 = 24 with 1 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C57A hexadecimal to binary:

C57A hexadecimal = 1100010101111010 binary

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C57B hexadecimal to binary
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