C54B hexadecimal to binary

Here we will show you how to convert the hexadecimal number C54B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C54B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C54B by 16⁰, multiply the second to last digit in C54B by 16¹, multiply the third to last digit in C54B by 16², multiply the fourth to last digit in C54B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
4 × 16¹ = 64
5 × 16² = 1280
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 64 + 1280 + 49152 = 50507

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

50507 ÷ 2 = 25253 with 1 remainder
25253 ÷ 2 = 12626 with 1 remainder
12626 ÷ 2 = 6313 with 0 remainder
6313 ÷ 2 = 3156 with 1 remainder
3156 ÷ 2 = 1578 with 0 remainder
1578 ÷ 2 = 789 with 0 remainder
789 ÷ 2 = 394 with 1 remainder
394 ÷ 2 = 197 with 0 remainder
197 ÷ 2 = 98 with 1 remainder
98 ÷ 2 = 49 with 0 remainder
49 ÷ 2 = 24 with 1 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C54B hexadecimal to binary:

C54B hexadecimal = 1100010101001011 binary

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C54C hexadecimal to binary
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