C38E hexadecimal to binary

Here we will show you how to convert the hexadecimal number C38E to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C38E from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C38E by 16⁰, multiply the second to last digit in C38E by 16¹, multiply the third to last digit in C38E by 16², multiply the fourth to last digit in C38E by 16³, and so on, until all the digits are used.

E × 16⁰ = 14
8 × 16¹ = 128
3 × 16² = 768
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

14 + 128 + 768 + 49152 = 50062

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

50062 ÷ 2 = 25031 with 0 remainder
25031 ÷ 2 = 12515 with 1 remainder
12515 ÷ 2 = 6257 with 1 remainder
6257 ÷ 2 = 3128 with 1 remainder
3128 ÷ 2 = 1564 with 0 remainder
1564 ÷ 2 = 782 with 0 remainder
782 ÷ 2 = 391 with 0 remainder
391 ÷ 2 = 195 with 1 remainder
195 ÷ 2 = 97 with 1 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C38E hexadecimal to binary:

C38E hexadecimal = 1100001110001110 binary

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C38F hexadecimal to binary
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