C38A hexadecimal to binary

Here we will show you how to convert the hexadecimal number C38A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C38A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C38A by 16⁰, multiply the second to last digit in C38A by 16¹, multiply the third to last digit in C38A by 16², multiply the fourth to last digit in C38A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
8 × 16¹ = 128
3 × 16² = 768
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 128 + 768 + 49152 = 50058

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

50058 ÷ 2 = 25029 with 0 remainder
25029 ÷ 2 = 12514 with 1 remainder
12514 ÷ 2 = 6257 with 0 remainder
6257 ÷ 2 = 3128 with 1 remainder
3128 ÷ 2 = 1564 with 0 remainder
1564 ÷ 2 = 782 with 0 remainder
782 ÷ 2 = 391 with 0 remainder
391 ÷ 2 = 195 with 1 remainder
195 ÷ 2 = 97 with 1 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C38A hexadecimal to binary:

C38A hexadecimal = 1100001110001010 binary

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C38B hexadecimal to binary
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