C2C1 hexadecimal to binary

Here we will show you how to convert the hexadecimal number C2C1 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C2C1 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C2C1 by 16⁰, multiply the second to last digit in C2C1 by 16¹, multiply the third to last digit in C2C1 by 16², multiply the fourth to last digit in C2C1 by 16³, and so on, until all the digits are used.

1 × 16⁰ = 1
C × 16¹ = 192
2 × 16² = 512
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

1 + 192 + 512 + 49152 = 49857

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

49857 ÷ 2 = 24928 with 1 remainder
24928 ÷ 2 = 12464 with 0 remainder
12464 ÷ 2 = 6232 with 0 remainder
6232 ÷ 2 = 3116 with 0 remainder
3116 ÷ 2 = 1558 with 0 remainder
1558 ÷ 2 = 779 with 0 remainder
779 ÷ 2 = 389 with 1 remainder
389 ÷ 2 = 194 with 1 remainder
194 ÷ 2 = 97 with 0 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C2C1 hexadecimal to binary:

C2C1 hexadecimal = 1100001011000001 binary

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C2C2 hexadecimal to binary
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