C2B8 hexadecimal to binary

Here we will show you how to convert the hexadecimal number C2B8 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C2B8 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C2B8 by 16⁰, multiply the second to last digit in C2B8 by 16¹, multiply the third to last digit in C2B8 by 16², multiply the fourth to last digit in C2B8 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
B × 16¹ = 176
2 × 16² = 512
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 176 + 512 + 49152 = 49848

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

49848 ÷ 2 = 24924 with 0 remainder
24924 ÷ 2 = 12462 with 0 remainder
12462 ÷ 2 = 6231 with 0 remainder
6231 ÷ 2 = 3115 with 1 remainder
3115 ÷ 2 = 1557 with 1 remainder
1557 ÷ 2 = 778 with 1 remainder
778 ÷ 2 = 389 with 0 remainder
389 ÷ 2 = 194 with 1 remainder
194 ÷ 2 = 97 with 0 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C2B8 hexadecimal to binary:

C2B8 hexadecimal = 1100001010111000 binary

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C2B9 hexadecimal to binary
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