C2B4 hexadecimal to binary

Here we will show you how to convert the hexadecimal number C2B4 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C2B4 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C2B4 by 16⁰, multiply the second to last digit in C2B4 by 16¹, multiply the third to last digit in C2B4 by 16², multiply the fourth to last digit in C2B4 by 16³, and so on, until all the digits are used.

4 × 16⁰ = 4
B × 16¹ = 176
2 × 16² = 512
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

4 + 176 + 512 + 49152 = 49844

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

49844 ÷ 2 = 24922 with 0 remainder
24922 ÷ 2 = 12461 with 0 remainder
12461 ÷ 2 = 6230 with 1 remainder
6230 ÷ 2 = 3115 with 0 remainder
3115 ÷ 2 = 1557 with 1 remainder
1557 ÷ 2 = 778 with 1 remainder
778 ÷ 2 = 389 with 0 remainder
389 ÷ 2 = 194 with 1 remainder
194 ÷ 2 = 97 with 0 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C2B4 hexadecimal to binary:

C2B4 hexadecimal = 1100001010110100 binary

Hexadecimal to Binary Converter
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