C258 hexadecimal to binary

Here we will show you how to convert the hexadecimal number C258 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert C258 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in C258 by 16⁰, multiply the second to last digit in C258 by 16¹, multiply the third to last digit in C258 by 16², multiply the fourth to last digit in C258 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
5 × 16¹ = 80
2 × 16² = 512
C × 16³ = 49152

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 80 + 512 + 49152 = 49752

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

49752 ÷ 2 = 24876 with 0 remainder
24876 ÷ 2 = 12438 with 0 remainder
12438 ÷ 2 = 6219 with 0 remainder
6219 ÷ 2 = 3109 with 1 remainder
3109 ÷ 2 = 1554 with 1 remainder
1554 ÷ 2 = 777 with 0 remainder
777 ÷ 2 = 388 with 1 remainder
388 ÷ 2 = 194 with 0 remainder
194 ÷ 2 = 97 with 0 remainder
97 ÷ 2 = 48 with 1 remainder
48 ÷ 2 = 24 with 0 remainder
24 ÷ 2 = 12 with 0 remainder
12 ÷ 2 = 6 with 0 remainder
6 ÷ 2 = 3 with 0 remainder
3 ÷ 2 = 1 with 1 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to C258 hexadecimal to binary:

C258 hexadecimal = 1100001001011000 binary

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C259 hexadecimal to binary
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