B9AF hexadecimal to binary




Here we will show you how to convert the hexadecimal number B9AF to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).


The four steps used to convert B9AF from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B9AF by 16⁰, multiply the second to last digit in B9AF by 16¹, multiply the third to last digit in B9AF by 16², multiply the fourth to last digit in B9AF by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
A × 16¹ = 160
9 × 16² = 2304
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 160 + 2304 + 45056 = 47535

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

47535 ÷ 2 = 23767 with 1 remainder
23767 ÷ 2 = 11883 with 1 remainder
11883 ÷ 2 = 5941 with 1 remainder
5941 ÷ 2 = 2970 with 1 remainder
2970 ÷ 2 = 1485 with 0 remainder
1485 ÷ 2 = 742 with 1 remainder
742 ÷ 2 = 371 with 0 remainder
371 ÷ 2 = 185 with 1 remainder
185 ÷ 2 = 92 with 1 remainder
92 ÷ 2 = 46 with 0 remainder
46 ÷ 2 = 23 with 0 remainder
23 ÷ 2 = 11 with 1 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B9AF hexadecimal to binary:

B9AF hexadecimal = 1011100110101111 binary


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