B917 hexadecimal to binary

Here we will show you how to convert the hexadecimal number B917 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B917 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B917 by 16⁰, multiply the second to last digit in B917 by 16¹, multiply the third to last digit in B917 by 16², multiply the fourth to last digit in B917 by 16³, and so on, until all the digits are used.

7 × 16⁰ = 7
1 × 16¹ = 16
9 × 16² = 2304
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

7 + 16 + 2304 + 45056 = 47383

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

47383 ÷ 2 = 23691 with 1 remainder
23691 ÷ 2 = 11845 with 1 remainder
11845 ÷ 2 = 5922 with 1 remainder
5922 ÷ 2 = 2961 with 0 remainder
2961 ÷ 2 = 1480 with 1 remainder
1480 ÷ 2 = 740 with 0 remainder
740 ÷ 2 = 370 with 0 remainder
370 ÷ 2 = 185 with 0 remainder
185 ÷ 2 = 92 with 1 remainder
92 ÷ 2 = 46 with 0 remainder
46 ÷ 2 = 23 with 0 remainder
23 ÷ 2 = 11 with 1 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B917 hexadecimal to binary:

B917 hexadecimal = 1011100100010111 binary

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B918 hexadecimal to binary
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