B77B hexadecimal to binary

Here we will show you how to convert the hexadecimal number B77B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B77B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B77B by 16⁰, multiply the second to last digit in B77B by 16¹, multiply the third to last digit in B77B by 16², multiply the fourth to last digit in B77B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
7 × 16¹ = 112
7 × 16² = 1792
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 112 + 1792 + 45056 = 46971

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

46971 ÷ 2 = 23485 with 1 remainder
23485 ÷ 2 = 11742 with 1 remainder
11742 ÷ 2 = 5871 with 0 remainder
5871 ÷ 2 = 2935 with 1 remainder
2935 ÷ 2 = 1467 with 1 remainder
1467 ÷ 2 = 733 with 1 remainder
733 ÷ 2 = 366 with 1 remainder
366 ÷ 2 = 183 with 0 remainder
183 ÷ 2 = 91 with 1 remainder
91 ÷ 2 = 45 with 1 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B77B hexadecimal to binary:

B77B hexadecimal = 1011011101111011 binary

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