B5F hexadecimal to binary

Here we will show you how to convert the hexadecimal number B5F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B5F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B5F by 16⁰, multiply the second to last digit in B5F by 16¹, multiply the third to last digit in B5F by 16², multiply the fourth to last digit in B5F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
5 × 16¹ = 80
B × 16² = 2816

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 80 + 2816 = 2911

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

2911 ÷ 2 = 1455 with 1 remainder
1455 ÷ 2 = 727 with 1 remainder
727 ÷ 2 = 363 with 1 remainder
363 ÷ 2 = 181 with 1 remainder
181 ÷ 2 = 90 with 1 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B5F hexadecimal to binary:

B5F hexadecimal = 101101011111 binary

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