B58B hexadecimal to binary

Here we will show you how to convert the hexadecimal number B58B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B58B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B58B by 16⁰, multiply the second to last digit in B58B by 16¹, multiply the third to last digit in B58B by 16², multiply the fourth to last digit in B58B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
8 × 16¹ = 128
5 × 16² = 1280
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 128 + 1280 + 45056 = 46475

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

46475 ÷ 2 = 23237 with 1 remainder
23237 ÷ 2 = 11618 with 1 remainder
11618 ÷ 2 = 5809 with 0 remainder
5809 ÷ 2 = 2904 with 1 remainder
2904 ÷ 2 = 1452 with 0 remainder
1452 ÷ 2 = 726 with 0 remainder
726 ÷ 2 = 363 with 0 remainder
363 ÷ 2 = 181 with 1 remainder
181 ÷ 2 = 90 with 1 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B58B hexadecimal to binary:

B58B hexadecimal = 1011010110001011 binary

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