B58 hexadecimal to binary

Here we will show you how to convert the hexadecimal number B58 to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B58 from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B58 by 16⁰, multiply the second to last digit in B58 by 16¹, multiply the third to last digit in B58 by 16², multiply the fourth to last digit in B58 by 16³, and so on, until all the digits are used.

8 × 16⁰ = 8
5 × 16¹ = 80
B × 16² = 2816

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

8 + 80 + 2816 = 2904

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

2904 ÷ 2 = 1452 with 0 remainder
1452 ÷ 2 = 726 with 0 remainder
726 ÷ 2 = 363 with 0 remainder
363 ÷ 2 = 181 with 1 remainder
181 ÷ 2 = 90 with 1 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B58 hexadecimal to binary:

B58 hexadecimal = 101101011000 binary

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B59 hexadecimal to binary
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