B53A hexadecimal to binary

Here we will show you how to convert the hexadecimal number B53A to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B53A from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B53A by 16⁰, multiply the second to last digit in B53A by 16¹, multiply the third to last digit in B53A by 16², multiply the fourth to last digit in B53A by 16³, and so on, until all the digits are used.

A × 16⁰ = 10
3 × 16¹ = 48
5 × 16² = 1280
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

10 + 48 + 1280 + 45056 = 46394

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

46394 ÷ 2 = 23197 with 0 remainder
23197 ÷ 2 = 11598 with 1 remainder
11598 ÷ 2 = 5799 with 0 remainder
5799 ÷ 2 = 2899 with 1 remainder
2899 ÷ 2 = 1449 with 1 remainder
1449 ÷ 2 = 724 with 1 remainder
724 ÷ 2 = 362 with 0 remainder
362 ÷ 2 = 181 with 0 remainder
181 ÷ 2 = 90 with 1 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B53A hexadecimal to binary:

B53A hexadecimal = 1011010100111010 binary

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B53B hexadecimal to binary
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