B47F hexadecimal to binary

Here we will show you how to convert the hexadecimal number B47F to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B47F from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B47F by 16⁰, multiply the second to last digit in B47F by 16¹, multiply the third to last digit in B47F by 16², multiply the fourth to last digit in B47F by 16³, and so on, until all the digits are used.

F × 16⁰ = 15
7 × 16¹ = 112
4 × 16² = 1024
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

15 + 112 + 1024 + 45056 = 46207

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

46207 ÷ 2 = 23103 with 1 remainder
23103 ÷ 2 = 11551 with 1 remainder
11551 ÷ 2 = 5775 with 1 remainder
5775 ÷ 2 = 2887 with 1 remainder
2887 ÷ 2 = 1443 with 1 remainder
1443 ÷ 2 = 721 with 1 remainder
721 ÷ 2 = 360 with 1 remainder
360 ÷ 2 = 180 with 0 remainder
180 ÷ 2 = 90 with 0 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B47F hexadecimal to binary:

B47F hexadecimal = 1011010001111111 binary

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