B45B hexadecimal to binary

Here we will show you how to convert the hexadecimal number B45B to a binary number. First note that the hexadecimal number system has sixteen different digits (0 1 2 3 4 5 6 7 8 9 A B C D E F) and the binary number system has only two different digits (0 and 1).

The four steps used to convert B45B from hexadecimal to binary are explained below.

Step 1)
Multiply the last digit in B45B by 16⁰, multiply the second to last digit in B45B by 16¹, multiply the third to last digit in B45B by 16², multiply the fourth to last digit in B45B by 16³, and so on, until all the digits are used.

B × 16⁰ = 11
5 × 16¹ = 80
4 × 16² = 1024
B × 16³ = 45056

Remember that the hexadecimal number system has sixteen different digits, so when doing the above calculation, we use the following values if applicable: A=10, B=11, C=12, D=13, E=14, and F=15.

Step 2)
Next, we add up all the products we got from Step 1, like this:

11 + 80 + 1024 + 45056 = 46171

Step 3)
Now we divide the sum from Step 2 by 2. Put the remainder aside. Then divide the whole part by 2 again, and put the remainder aside again. Keep doing this until the whole part is 0.

46171 ÷ 2 = 23085 with 1 remainder
23085 ÷ 2 = 11542 with 1 remainder
11542 ÷ 2 = 5771 with 0 remainder
5771 ÷ 2 = 2885 with 1 remainder
2885 ÷ 2 = 1442 with 1 remainder
1442 ÷ 2 = 721 with 0 remainder
721 ÷ 2 = 360 with 1 remainder
360 ÷ 2 = 180 with 0 remainder
180 ÷ 2 = 90 with 0 remainder
90 ÷ 2 = 45 with 0 remainder
45 ÷ 2 = 22 with 1 remainder
22 ÷ 2 = 11 with 0 remainder
11 ÷ 2 = 5 with 1 remainder
5 ÷ 2 = 2 with 1 remainder
2 ÷ 2 = 1 with 0 remainder
1 ÷ 2 = 0 with 1 remainder

Step 4)
In the final step, we take the remainders from Step 3 and put them together in reverse order to get our answer to B45B hexadecimal to binary:

B45B hexadecimal = 1011010001011011 binary

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